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node js return received data in-rest api response

i create simple rest api to return media file

var fs = require('fs')
var express = require('express')
var app = express()
app.get('/file.ogg', function (req, res)
res.set(
'Content-Type': 'audio/ogg',
'Transfer-Encoding': 'chunked'
);

var inputStream = fs.createReadStream(__dirname + '/1.ogg');
inputStream.pipe(res);
);

var server = app.listen(3002);


if i call http://127.0.0.1:3002/file.ogg

server read file 1.ogg and return it in response.

now i use websocket to get file data from external device

socket.on('message', function incoming(message)

var data = JSON.parse(message);
console.log('fileName: ' + data.fileName);
console.log('fileData : ' + data.fileData.length);

var path =__dirname + '/_' + data.fileName;
var buf = Buffer.from(data.fileData, 'base64');

console.log('buf : ' + buf.length);

// save data to file
fs.appendFile(path ,buf ,function(err)
if(err) throw err;
);

);


i want to return data (buf) in response like first example but without saving any think, how i can do this.

1 Answer
1

If your files are large, you may want to pull in an additional websocket streaming library which will allow you to stream the data back to the client. socket.io-stream was created specifically to allow that. From their examples:

// send data
ss(socket).on('file', function(stream)
fs.createReadStream('/path/to/file').pipe(stream);
);

// receive data
ss(socket).emit('file', stream);
stream.pipe(fs.createWriteStream('file.txt'));


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