remove multiple consecutive occurrences of .* in a string with a single .* python
Clash Royale CLAN TAG#URR8PPP
remove multiple consecutive occurrences of .* in a string with a single .* python
Below is my code to check for the multiple consecutive occurrences of ".*"
in string. If there are multiple consecutive occurrences of ".*" then replace it with single ".*". Forg:
".*"
".*"
".*"
import re
dot_star_check = re.compile('(.*)2,')
k = ".*.*.*.*.*foo.*"
k = k.replace(?,".*") if dot_star_check.search(k) else k
print k
What i should write instead of ? to replace multiple consecutive occurrences of .* with single .*
.*
.*
So, expected output is .*foo.*
.*foo.*
other egs:
1.) foo.*.*.*.*bar.* ->foo.*bar.*
foo.*.*.*.*bar.* ->foo.*bar.*
2.) .*foobar.*.*.*.*.* ->.*foobar.*
.*foobar.*.*.*.*.* ->.*foobar.*
2 Answers
2
You can use re.sub and (?:.*)+ as your pattern:
re.sub
(?:.*)+
import re
dot_star_check = re.compile('(?:.*)+')
k = ".*.*.*.*.*foo.*"
k = re.sub(dot_star_check,'.*',k)
print (k)
Prints:
.*foo.*
You could additionally improve the efficiency of the pattern so that substitution is performed only when there are 2 or more occurences using (?:.*)2, :
(?:.*)2,
import re
dot_star_check = re.compile('(?:.*)2,')
k = ".*.*.*.*.*foo.*"
k = re.sub(dot_star_check,'.*',k)
print (k)
Prints:
.*foo.*
It is a non capturing group. Using a non capturing group is generally more efficient than using a capturing group.
– UnbearableLightness
Aug 10 at 22:25
multiple consecutive occureences of .* is equivalent to single .* right?
– zubug55
Aug 10 at 22:28
I am not sure I follow, could you please clarify? What do you mean by your comment?
– UnbearableLightness
Aug 10 at 22:30
I am trying to look for data matching patterns -> .*.*.*.*foo.*.* or bar.*.*.*foo.*.*.* or anything else ; so instead of making a search with the above regexp strings; i am removing multiple consecutive .* with single .*? so , i am asking if there is any difference between .*.*.*.*foo.*.* and .*foo.* or not? I am doing this to make search efficient
– zubug55
Aug 10 at 22:35
I think you can just use re.sub and (.*)+ as your regex:
re.sub
(.*)+
s = 'foo.*.*.*.*bar.*'
s2 = '.*foobar.*.*.*.*.* '
k = ".*.*.*.*.*foo.*"
>>> re.sub('(.*)+','.*',s)
'foo.*bar.*'
>>> re.sub('(.*)+','.*',s2)
'.*foobar.* '
>>> re.sub('(.*)+','.*',k)
'.*foo.*'
Using a character set in this case is not correct, since it would also match
*. for instance rather than .*.– UnbearableLightness
Aug 10 at 22:21
*.
.*
You're right, my mistake, edited
– sacul
Aug 10 at 22:22
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why u have ? and : at the start?
– zubug55
Aug 10 at 22:24