Returning a single value from a filter

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Returning a single value from a filter



I am trying to return a single value from a filter that returns a large object.


return data.filter(subject => subject.id === 1)
.map((subject) =>
return subject.total.toString();
);



I have tried, toString, JSON.parse and a few more but always get it either as a single array value.



[112]



or a string inside the array



["112"]



but not a single returned value



112



Is map the wrong method? How do I return a pure integer or string would do?





The docs of filter function says that its return type is array developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/…
– Ionut
Aug 8 at 13:05



filter


array




4 Answers
4



You just need to pick the first element. This should suffice..


return data.filter(subject => subject.id === 1)[0].total+""





Good answer, thanks I prefer "find" though
– leblaireau
Aug 8 at 13:54






find is also more performant, because it stops as soon as it finds a match. Filter will continue and process the whole array anyway.
– Jeremy Thille
Aug 8 at 19:00


find



Instead of filter which returns an array with filtered values, use find:


filter


find


const subject = data.find(subject => subject.id === 1);
return subject.total.toString();



or shorter:


return data.find(subject => subject.id === 1).total.toString();



What about


return data
.filter(subject => subject.id === 1)
.map(subject => subject.total.toString())[0] // Take the first element of the array :)



Array.map returns an array. If your initial array contains one element, the output array will also contain one element. Just extract it with [0].


Array.map


[0]



Alternatively. find() returns one object :


find()


return data.find(subject => subject.id === 1).total.toString()



Filter will always return a array to get the first element use pop


pop


return data.filter(subject => subject.id === 1)
.map((subject) =>
return subject.total;
).pop();






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