Clash Royale CLAN TAG#URR8PPP

Pick data from array of objects and return new object

So, I have:

"people": [

"first": "Linda",
"last": "Donson",
"salary": "4000USD"
,

"first": "Mark",
"last": "Sullivan",
"salary": "3500USD"
,
];


Now, I want to convert this into a new array of objects, containing only desired set of data.
For example:

"people": [

"first": "Linda",
"salary": "4000USD"
,

"first": "Mark",
"salary": "3500USD"
,
];


How can I do this? So, it should take out the "last" key and its values and return only "first" and "last".

"last"

"first"

"last"

Thanks

3 Answers
3

This really is a simple one liner via map and delete or map and ES6 destructuring as shown in the 2 examples bellow:

map

delete

map

destructuring

var data = [
"first": "Linda",
"last": "Donson",
"salary": "4000USD"
,

"first": "Mark",
"last": "Sullivan",
"salary": "3500USD"

]

console.log(data.map(x => delete(x.salary) && x))

Also if you are concerned about mutating the object you can simply use ES6 destructuring and the short object literal notation to get this:

destructuring

short object literal notation

Object.values(data).map((first, last) => (first, last))


you can use map function to get a new array with your desired options
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/map

var source = [ first: 'first1', last: 'last1', property1: 'p1-1' , first: 'first2', last: 'last2', property1: 'p1-2' ];

var mapped = source.map( function (e)
return first: e.first, property1: e.property1
)

console.log('mapped : ', mapped)

You can use forEach

var peoples = [
"first": "Linda",
"last": "Donson",
"salary": "4000USD"
,

"first": "Mark",
"last": "Sullivan",
"salary": "3500USD"
,
];


// empty array
var newPeoples = ;


peoples.forEach((people) =>

// only push desired object inside empty array
newPeoples.push(
"first": people.first,
"salary": people.salary
);

);


// desired array of objects
console.log(newPeoples);


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