Not able to access WSO2 IoTS Device Management Console in wso2-iot-3.3.0 when logged in 'admin'

The name of the pictureThe name of the pictureThe name of the pictureClash Royale CLAN TAG#URR8PPP



Not able to access WSO2 IoTS Device Management Console in wso2-iot-3.3.0 when logged in 'admin'



I am studying IOT-server. I have a question and please help me.
I use WSO2 IoT server and I am not able to access WSO2 IoT server device Management Console (https://localhost:9443/devicemgt) when I input 'admin' both username and password or input this which created a new account.

As a result, it showed me the Authentication failed. When I saw users list in https://localhost:9443/carbon, it showed admin, new accounts .... etc.
I don't know why it does not log in WSO2 IoT server device Management Console.
Please give your advice and then thank you so much.




1 Answer
1



You need to check Java version, All wso2 Products have issues with the latest version of Java, if you are using java version "1.8.0_151" then that's a problem, try using java version "1.8.0_144".
If you cannot change java version then you need to change the compression parameter to off in catalina-server.xml file


java version "1.8.0_151"


java version "1.8.0_144"


compression parameter to off


catalina-server.xml





Thank you so much. I tried that. I saw java version "1.8.0_181" and compression ="off" . I modified that. Perfectly it does well. Thank you so much again.
– LYB
Aug 10 at 7:23





Welcome, can you accept the answer so that it will be helpful for others as well.
– amg_amit
Aug 10 at 7:33






By clicking "Post Your Answer", you acknowledge that you have read our updated terms of service, privacy policy and cookie policy, and that your continued use of the website is subject to these policies.

-

Popular posts from this blog

Firebase Auth - with Email and Password - Check user already registered

Image
Clash Royale CLAN TAG #URR8PPP Firebase Auth - with Email and Password - Check user already registered I want to check when a user attempts to signup with createUserWithEmailAndPassword() in Firebase user Authentication method, this user is already registered with my app. createUserWithEmailAndPassword() 8 Answers 8 To detect whether a user with that email address already exists, you can detect when the call to createUserWithEmailAndPassword () fails with auth/email-already-in-use . I see that @Srinivasan just posted an answer for this. createUserWithEmailAndPassword () auth/email-already-in-use Alternatively, you can detect that an email address is already used by calling fetchSignInMethodsForEmail() (previous called fetchProvidersForEmail() ). fetchSignInMethodsForEmail() fetchProvidersForEmail() When the user trying to create an user with same email address, the task response will be "Response: The email address is already in use by another account." mFirebas
Read more

Dynamically update html content plain JS

Image
Clash Royale CLAN TAG #URR8PPP Dynamically update html content plain JS So I have a script bound in my index.html, which literally has to fetch an array of jsons from an api, then dynamically update my page when get response. But as a result I'm getting an as the only update of my page. here is my script fetch(url) .then((resp) => resp.json()) .then((resp) => resp.results.forEach(item => fetch(item.url) .then((response)=> response.json()) .then((response) => pokeArr.push(response)) .catch(console.log) ) ).catch(console.log) const filler = () => if(!pokeArr) return 0 pokeArr.map((i,j)=> return `<tr>$i.name</tr>` ) const pokeindex = () => document.getElementById('a').appendChild(document.createElement(filler())) pokeindex() When I'm consoling it, I can see in the console all the responses I get, so I'm at least doing the fetching part right. What's parberakan ? What's pokeArr ? – T.J. Crowder Aug 8 at 12
Read more

How to determine optimal route across keyboard

Image
Clash Royale CLAN TAG #URR8PPP How to determine optimal route across keyboard I'm trying to automate the typing process in a video game. Players are given an on-screen QWERTY keyboard layout that they can navigate with the control stick (up, down, left, right) in order to select a letter to type. I was wondering if there was a module for Python (or some other resource I could explore) that would help my program find a path across the keyboard as it types each letter in a given message. In other words, if the first letter typed was "A" and the next letter was "B", the module would know that the program should move 1 space down on the keyboard and 4 spaces to the right. Currently, I have the program resetting to the "G" key after each letter is typed (allowing me to use fixed-directions as the program parses each character in the desired message). As you can imagine, this is quite inefficient and defeats the purpose of automating the typing in the fir
Read more