How to make thread safe code block in swift

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How to make thread safe code block in swift



I tried multiple solution/answers given on stackoverflow but none of them worked for me. Some of them is as below :



https://stackoverflow.com/a/30495424/3145189



Is this safe to call wait() of DispatchSemaphore several times at one time?



https://stackoverflow.com/a/37155631/3145189



I am trying to achieve very simple thing, code block or function should execute serially, regardless of from which thread it's been called.



My Example code :


func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplicationLaunchOptionsKey: Any]?) -> Bool

DispatchQueue.global().async
self.testLog(name:"first")

DispatchQueue.global().async
self.testLog(name:"second")


DispatchQueue.main.async
self.testLog(name: "mainthread")




func testLog(name:String) -> Void
for i in 1..<1000
print("thread test (i) name =(name)")





So output should be like -



first thread call



thread test 1 name =first



thread test 2 name =first



thread test 3 name =first



.



.



.



thread test 999 name =first



second thread call



thread test 1 name =second



thread test 2 name =second



.



.



.



thread test 999 name =second



main thread call



thread test 1 name =mainthread



thread test 2 name =mainthread



.



.



.



thread test 999 name =mainthread



If function is called on first thread, it should continue print log for the first thread only. Order of thread can vary I don't care means even if it's print mainthread log first then second and first doesn't matter logs should be grouped.





i have tried multiple things, but not mentioned in example code in my question, so requesting you please test you answer before posting
– shesh nath
Aug 10 at 7:11





create a serial queue and add testLog() to the queue.
– vivekDas
Aug 10 at 7:32




2 Answers
2



I am trying to achieve very simple thing, code block or function should execute serially, regardless of from which thread it's been called.



To execute serially you use a Dispatch serial queue. If you were writing a class or struct you could use a static let at class/struct level to store your queue in which your serialising function could dispatch to. A static let in this case is equivalent to a "class variable" in some languages.


static let


static let



If you were writing in (Objective-)C such variables can also be declared at the function level, that is a variable with global lifetime but with scope limited to within the function. Swift does not support these within a function, but you can scope a struct to a function...


func testLog(name:String) -> Void

struct LocalStatics

static let privateQueue = DispatchQueue(label: "testLogQueue")


// run the function body on the serial queue - could use async here
// and the body would still run not interleaved with other calls but
// the caller need not wait for it to do so
LocalStatics.privateQueue.sync
for i in 1..<1000

print("thread test (i) name =(name)")





(For a debate on "local statics" in Swift see this SO Q&A)



This will execute the calls serially.
Keep a reference to serialQueue and you can submit blocks from any thread.


serialQueue


let serialQueue = DispatchQueue(label: "serial_queue")

serialQueue.async
self.testLog(name: "first")

serialQueue.async
self.testLog(name: "second")


serialQueue.async
self.testLog(name: "third")





Can do like-> serialQueue.async self.testLog(name: "first") self.testLog(name: "second") self.testLog(name: "third") in one async block only.
– vivekDas
Aug 10 at 7:32






that is true, but i was trying to demo that each async call can be made from different threads in different places in the code
– Aris
Aug 10 at 7:36


async






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