Clash Royale CLAN TAG#URR8PPP

Extract value of get parameter in shell

I have an input that could either be dn3321 or
https://domaincom/file?tag=dn3321 and I'm trying to parse the value of tag using shell.

dn3321

https://domaincom/file?tag=dn3321

Looks like a regex could do the trick, how would I write a one liner to detect if it's a URL if it is apply the regex to extract the value and if its not just use the value directly.

2 Answers
2

It's unclear from the question what the full space of possible inputs looks like, but, for the simple cases you gave, you can use parameter expansion:

#!/usr/bin/env bash

in1='dn3321'
in2='https://domaincom/file?tag=dn3321'

echo "$in1#*="
echo "$in2#*="
# prints "dn3321" twice


This works by removing the first = and any text preceding it.

=

ftp://domaincom/file?tag=dn3321

https://domaincom/file?tag=dn3321&foo=bar

https://otherdomain.com/foo?bar=bat&tag=dn3321

If you just need to print out a very specific part of the string that is a url you can do it like this:

#!/bin/bash
url="https://domaincom/file?tag=dn3321"

if [[ "$url" =~ "$http,," ]] ; then
tag=$(echo $url | cut -d'=' -f2)
fi


if you need something more elaborate I can post an example.

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