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Force type to be integer and not float in python

I am writing a simple program that will calculate the sum of the digits. So for example 123 would be 1 + 2 + 3 = 6 simple. When I write my code

123

1 + 2 + 3 = 6

def sumOfNumber(number):
sum = 0

while(number >= 1):
temp = number % 10
sum += temp
number /= 10

return sum

main():
sumOfNumber(123)
# 6.53


Can anyone explain this?

2 Answers
2

You seem to be using Python3 where division / outputs floats. Replace the inplace division /= with integer division //= to get rid of decimals.

/

/=

//=

number //= 10


Although, if you want to manipulate a number digit by digit, it is better to cast it to a str. This allows to loop over its digits and sum them.

str

def sumOfNumber(number):
digits = str(number)
sum_ = 0

for d in digits:
sum_ += int(d)

return sum_

sumOfNumber(123) # 6


Using the builtin sum function, you can even rewrite this function in a single line.

sum

def sumOfNumber(number):
return sum(int(x) for x in str(number))


//

I ended up just casting it, but if someone has a better solution please post as well.

def sumOfNumber(number):
sum = 0
while(number >= 1):
temp = int(number % 10)
sum += temp
number = int(number / 10)

return sum

main():
sumOfNumber(123)
# 6


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