Clash Royale CLAN TAG#URR8PPP

Returning an object from a function is not working as expected

For example

function a()
return
testing:1
;


function b()
return

testing:1
;



In the above code the function a() returns an object of testing:1, but the function b() returns the value of undefined. What is the reason behind this behaviour?

Is it because the return value starts in the second line?

3 Answers
3

Yes, is happening because when the interpreter runs the b function an see the return expression an anything near, it return undefined.

b

return

undefined

The return statement is affected by automatic semicolon insertion (ASI). No line terminator is allowed between the return keyword and the expression.

Put multi-line return in () brackets:

return

()

function a()
return (
testing:1
);


function b()
return(

testing:1
);

console.log(a());
console.log(b());

Javascript can be funky at times, but just having return at the end of a function returns, just returns nothing/null/undefined. I think your case the space between return and { is causing it to return anyway, despite the array there.

return

Like your function a(), have it typed like this:

function a()

function a()
return
testing:1
;


function b()
return
testing:1
;



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