Stuck on SQL Server procedure code

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Stuck on SQL Server procedure code



I'm getting an error from this code


DECLARE @existingEmail AS INT

SET NOCOUNT ON;

@existingEmail = COUNT(*) AS total FROM table WHERE email = @email;

INSERT INTO table2 (email)
VALUES (CASE WHEN @existingEmail IS 1 THEN 'Yes' ELSE 'No' END);



That is the error I am getting



Msg 102, Level 15, State 1, Procedure sp_counts, Line 21 [Batch Start Line 7]

Incorrect syntax near '@existingEmail'.





Do you really want to insert a new row or update an existing row?
– Aaron Dietz
Aug 8 at 18:20


insert


update





@existingEmail = COUNT(*) AS total FROM table WHERE email = @email; Where's the word SELECT??
– Eric
Aug 8 at 18:37



@existingEmail = COUNT(*) AS total FROM table WHERE email = @email;


SELECT




3 Answers
3



Using COUNT to check existence may not be best idea from performance point of view:


COUNT


INSERT INTO table2 (email)
SELECT CASE WHEN EXISTS (SELECT 1 FROM table WHERE email = @email) THEN 'Yes'
ELSE 'No' END



Instead of this:


@existingEmail = COUNT(*) as total from table where email = @email;



You need to do this:


SELECT @existingEmail = COUNT(*) as total from table where email = @email;



or this:


SET @existingEmail = (SELECT COUNT(*) as total from table where email = @email);





after using set or select, I am still getting an error: Msg 156, Level 15, State 1, Procedure sp_counts, Line 21 [Batch Start Line 7] Incorrect syntax near the keyword 'from'. Msg 102, Level 15, State 1, Procedure sp_counts, Line 25 [Batch Start Line 7] Incorrect syntax near '1'.
– JDOB
Aug 8 at 18:21


Msg 156, Level 15, State 1, Procedure sp_counts, Line 21 [Batch Start Line 7] Incorrect syntax near the keyword 'from'. Msg 102, Level 15, State 1, Procedure sp_counts, Line 25 [Batch Start Line 7] Incorrect syntax near '1'.





I don't see anything wrong near the FROM in the code you posted, so probably you obfuscated it. As for the 1 you should be using = 1 instead of IS 1.
– Tab Alleman
Aug 8 at 18:24



FROM


1


= 1


IS 1



On the line where you are trying to set your variable @existingEmail you are missing the key word set. if you update that line to the following this should resolve that error.


@existingEmail


set


set @existingEmail = (SELECT COUNT(*) from table where email = @email);





this would be a much better answer if you could elaborate on why you proposed this as the solution and what it is doing. not a just code answer
– workabyte
Aug 8 at 19:18





I felt there was no need to elaborate,since the other comments covered the "why" of it.
– user1443098
Aug 8 at 19:36






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