By-passing Route Guard: Angular 5
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By-passing Route Guard: Angular 5
I'm using a route guard which is taking care of all the routes of one of my module. But, in a particular scenario where I know the route I'm accessing is a valid route, I would like to disable the route guard in that case. I'm using:
router.navigate(url)
for navigating to that url but would like to by pass the route guard in this case. Is there a standard or 'best-practice' way to do this?
exceptional valid route
Thanks for the help @AmitChigadani. But cannot do that because the 'id' in the route will be dynamic, and I don't want to remove route guard check from that route completely as it may be invalid when in the future. But the use case I described for sure knows that the route will be valid. So I would like to by pass only in that case.
– Aiguo
Aug 8 at 18:24
You cannot disable route for a scenario. You can completely remove it from the route which you don't want. Suggestion is allow to execute route guard and return true in canActivate method
– Suresh Kumar Ariya
Aug 8 at 18:35
1 Answer
1
You can use custom conditions in your guard like so :
canActivate(
route: ActivatedRouteSnapshot,
state: RouterStateSnapshot)
: boolean | Observable<boolean> | Promise<boolean>
if (route.url === 'unique/route/not/to/guard')
return true;
else
// ... Your logic
If your route is complicated (with ids and whatnot), consider using regexp.exec to check the validity.
regexp.exec
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You can add the check for
exceptional valid routein your guard itself and simply return if that route is found.– Amit Chigadani
Aug 8 at 18:22