Clash Royale CLAN TAG#URR8PPP

How would I make a list of tuples of size three into key-value pairs?

Objective:

1st number: Key to the second number

2nd number: Value to the first number but key to the third number

3rd number: Value to the second number

def make_dictionary_list(old_list):
return key: values for key, *values in old_list


Input:
[(4157, 1, 1), (4157, 1, 10), (4157, 2, 1), (4157, 2, 10), (4157, 3, 1), (4157, 3, 10), (4157, 4, 1), (4157, 4, 10), (4182, 1, 1)]

[(4157, 1, 1), (4157, 1, 10), (4157, 2, 1), (4157, 2, 10), (4157, 3, 1), (4157, 3, 10), (4157, 4, 1), (4157, 4, 10), (4182, 1, 1)]

Output:
4157: [4, 10], 4182: [1, 1]

4157: [4, 10], 4182: [1, 1]

The output is not what I want. As stated above, I'd like the 1st number being key to the 2nd number and 2nd number being the key to the 3rd number. How would I go about doing that?

Thanks!

1 Answer
1

You unravel your list:

data = [(4157, 1, 1), (4157, 1, 10), (4157, 2, 1), (4157, 2, 10), (4157, 3, 1), (4157, 3, 10), (4157, 4, 1), (4157, 4, 10), (4182, 1, 1)]

d =
for k,v,p in data:
key = d.setdefault(k,)
key[v]=p

print(d)


Output:

4157: 1: 10, 2: 10, 3: 10, 4: 10, 4182: 1: 1


The result is shorter then your sourcedata because you redefine the values of your inner dict for:

(4157, 1, 1) => (4157, 1, 10)
(4157, 2, 1) => (4157, 2, 10)
(4157, 3, 1) => (4157, 3, 10)
(4157, 4, 1) => (4157, 4, 10)


The first value gets replaced by the second one. You could aggregate them like so:

for k,v,p in data:
key = d.setdefault(k,)
key2 = key.setdefault(v,)
key2.append(p)

print(d)


To get an output of:

4157: 1: [1, 10], 2: [1, 10], 3: [1, 10], 4: [1, 10], 4182: 1: [1]


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