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Find first time that hasn't passed in array PHP

Let's say I have an array of times in PHP. How would I find the first time that hasn't passed yet?

For example, if the time is 3:20 PM and I have an array like this:

3:00 PM, 3:15 PM, 3:30 PM


The output would be 3:30 PM.

$times = array("3:00 PM", "3:15 PM")

2 Answers
2

there are few way to do this but here are some steps you can use.

Step 1. Convert each element/value of time in the array to a timestamp using strtotime. (you can add today's date to the beginning of each time string to achieve this)

Step 2. Compare each element against the current time using time if the element is is greater than current time now save it too a new array.

Step 3. Find the smallest number in the new array using min .

Step 4. Convert this smallest value back to time using date.

This is a good use case, where a filter solution works well. PHP has the array_filter function that is built to derive a solution array from a source array using a filtration function callback:

// $times = array() of the strtotimes. They don't need to be sorted
$available = array();

function filterByNow($time)
return($time > strtotime('now'));


$available = array_filter(sort($times, SORT_NUMERIC), 'filterByNow');


So long as $available is not an empty array, the $available[0] element is your first time.

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