Rearrange the string

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Rearrange the string



For Example-



input1 String ="2a[2b[c]]" then output should be "abcbcabcbc"


String ="2a[2b[c]]"


abcbcabcbc



input2 String ="2a[b[c]]" then output should be "abcabc"


String ="2a[b[c]]"


abcabc




import java.util.*;
class a

public static void main(String args)
String s = "2a[2b[c]]]";
// o/p = abcbcabcbc
Stack s1 = new Stack();
for(int i=0;i<s.length();i++)
s1.push(s.charAt(i));

String str="";
String sss="";
for(int j=0;j<s.length();j++)
char a = (char)s1.pop();
// if(a == '')
if((int)a >=49 && (int)a<=58)
for(int i=0;i<(int)a-48;i++)
sss+=str;
System.out.println(sss);


else if((int)a >=97 && (int)a <= 122)
str = a + str;
System.out.println(str);


System.out.println(sss);




but my output is showing like "bcbcabcabc".





Please explain what is the logic to get from "2a[2b[c]]" to "abcbcabcbc".
– Guy
Aug 8 at 8:10



"2a[2b[c]]"


"abcbcabcbc"





This is not an explanation, just another example. Currently your question is not clear enough to help you.
– Guy
Aug 8 at 8:14






2a[2b[c]] it should print 2 times of abc and 2 times of bc like abcbc , abcbc and o/p be abcbcabcbc
– arun kumar
Aug 8 at 8:22





1 Answer
1



Before you do sss+=str;,please add sss=str;.
you forget to update your sss.


sss+=str;


sss=str;


sss


public static void main(String args)
String s = "2a[2b[c]]]";
Stack s1 = new Stack();
for(int i=0;i<s.length();i++)
s1.push(s.charAt(i));

String str="";
String sss="";
for(int j=0;j<s.length();j++)
char a = (char)s1.pop();
System.out.println("a:"+a);
// if(a == '')
if((int)a >=49 && (int)a<=58)
for(int i=0;i<(int)a-48;i++)
sss=str;
sss+=str;
System.out.println("sss:"+sss);

str=sss;

//character
else if((int)a >=97 && (int)a <= 122)
str = a + str;
System.out.println("str:"+str);


System.out.println(sss);






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