Add active class to submenu on click in angular 4

The name of the pictureThe name of the pictureThe name of the pictureClash Royale CLAN TAG#URR8PPP



Add active class to submenu on click in angular 4



I have created a nested menu in Angular 4. I am facing problem with active class. Here is my code.



My code



I am able to add active class to main link but what should I do to add active class to submenu based on click. Please help





Clicking on second menu and third menu shows the submenu...then what you want?
– Onkar
Aug 8 at 6:45






On click of submenu clicked submenu should be active. what should I do for that
– vedankita kumbhar
Aug 8 at 6:52




1 Answer
1



You can make an object to store what is selected for main link and sub link and then apply the class accordingly.


main


sub



For example, you may pass main as an argument to tell that it is a main link and check isActive accordingly for main itself.


main


isActive


main


(click)="select('main', n.name);" [ngClass]="active: isActive('main', n.name)"



Similarly, it can be done for the sub link.


sub



Your functions could be as follows:-


select(type, item, $event)
this.selected[type] = (this.selected[type] === item ? null : item);
$event ? $event.stopPropagation() : null;

isActive(type, item)
return this.selected[type] === item;



You may stop propagation when selecting the sub link which is optional, I suppose (Kindly test for your use case).



Please check the code below:-



https://stackblitz.com/edit/angular-7b7cwd?file=src/app/app.component.html





Thank u so much @Ankit :)
– vedankita kumbhar
Aug 8 at 7:15





Glad that it helped. :)
– Ankit Sharma
Aug 8 at 7:15





There is one problem. Please check in this condition. click on one sub menu the open second main menu.
– vedankita kumbhar
Aug 8 at 7:17






That is because both sub menus have the same value as Sub Menu 1. Kindly try changing the values for the sub menus. I have changed it in the example for you. Please check now. You need to pass something else to identify it easily and correctly.
– Ankit Sharma
Aug 8 at 7:21



Sub Menu 1





Ok thank you :) working fine
– vedankita kumbhar
Aug 8 at 7:24







By clicking "Post Your Answer", you acknowledge that you have read our updated terms of service, privacy policy and cookie policy, and that your continued use of the website is subject to these policies.

Popular posts from this blog

Firebase Auth - with Email and Password - Check user already registered

Dynamically update html content plain JS

Creating a leaderboard in HTML/JS