Clash Royale CLAN TAG#URR8PPP

JavaScript Pattern Matching with Asterisks

I want to make something that would check if a string like this:

https://www.example.com/page

https://www.example.com/page

Is equal to:

http*//*example.com/*

http*//*example.com/*

Or something like this.
Is there something built in to JS that does this with asterisks, or should I use a plugin or something?

*

3 Answers
3

There's nothing built in that does what you've literally described. But look at regular expressions, which are the generalized version. The regular expression in your case would probably be /^http.*//.*example.com.*$/.

/^http.*//.*example.com.*$/

Example:

var rex = /^http.*//.*example.com.*$/;
function test(str)
console.log(str, rex.test(str));

test("https://www.example.com/page"); // true
test("ttps://www.example.com/page"); // false

You can try match() function

match()

let str = 'https://www.example.com/page';

let strMatches = str.match( /http([sS]*?)//([sS]*?)example.com([sS]*?)/ );

let result = document.querySelector('#result');
if( strMatches!= null && strMatches.length > 0 )
result.innerHTML = 'Match';
else
result.innerHTML = 'Mismatch';


<div id="result"></div>

I was able to create a function that does this, but thank you all for your answers. I will post the code below.

var wildcardCheck = function(i, m)
var regExpEscape = function(s) \()[]^$+*?.]/g, '\$&');
;
var m = new RegExp('^' + m.split(/*+/).map(regExpEscape).join('.*') + '$');
return i.match(m) !== null && i.match(m).length >= 1;
;


By clicking "Post Your Answer", you acknowledge that you have read our updated terms of service, privacy policy and cookie policy, and that your continued use of the website is subject to these policies.