How to use Group by in LINQ subquery with multi table joins?

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How to use Group by in LINQ subquery with multi table joins?



I am trying to learn LINQ and I went to couple of posts dealing with same issue but cant wrap my head around it.



How do I write below query in LINQ?


SELECT 1
FROM A
WHERE NOT EXISTS (SELECT 1
FROM B
JOIN C ON C.id = B.c_id
JOIN D ON D.id = C.d_id
WHERE A.b_id = B.id
AND D.Active = 1
GROUP BY B.id
HAVING COUNT(D.id) >= 5)



Edit : I looked into Group by in LINQ but I am not sure how I will have access to B.c_id after the group by and select caluses. How do I join to tables C and D?





If you're using an ORM like Entity Framework then the joins will be taken care of for you, assuming the foreign keys are setup correctly.
– BurnsBA
Aug 6 at 16:15





Yes I can handle that part, I am not sure on where to add group by and how to use having count.
– Quick-gun Morgan
Aug 6 at 16:16





Then you should be able to use Where on a GroupBy result: stackoverflow.com/a/2078745/1462295 and also stackoverflow.com/a/7325306/1462295
– BurnsBA
Aug 6 at 16:19


Where


GroupBy





Possible duplicate of Group by in LINQ
– Chad
Aug 6 at 16:30





@Quick-gunMorgan - you should probably start with a query that returns the information you are asking for.
– Chad
Aug 6 at 16:39




1 Answer
1



Try following. I used classes to make it easier to understand


class Program

static void Main(string args)

List<A> aS = new List<A>();
List<B> bS = new List<B>();
List<C> cS = new List<C>();
List<D> dS = new List<D>();

var temp = (from b in bS
join c in cS on b.id equals c.id
join d in dS on b.id equals d.id
select new b = b, c = c, d = d )
.GroupBy(x => x.b.id)
.Where(x => x.Any(y => y.d.Active == 1) && (x.Count() >= 5))
.ToList();

var results = aS.Where(x => !temp.Any(y => y.First().b.id == x.id)).ToList();





public class A

public int id get; set;

public class B

public int id get; set;

public class C

public int id get; set;

public class D

public int id get; set;
public int Active get; set;





Yes, this is what I was trying to understand. Thanks!
– Quick-gun Morgan
Aug 6 at 19:03






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