How to check connectivity of a directed graph in Python?

The name of the pictureThe name of the pictureThe name of the pictureClash Royale CLAN TAG#URR8PPP



How to check connectivity of a directed graph in Python?



Is there any way in Python's networkx to check for connectivity of a directed graph? If not in networkx, how else may this be achieved in Python?





There is the subpackage networkx.connectivity — have you checked there?
– L3viathan
Aug 13 at 8:29


networkx.connectivity





I believe that only operates on undirected graphs. I think the is_strongly_connected function will provide me with what I am seeking. I would really like to know how this works though? i.e. what algorithms does it use to calculate the result?
– BRavos
Aug 15 at 7:50





Nevermind, found it here: networkx.github.io/documentation/latest/_modules/networkx/…
– BRavos
Aug 15 at 8:14









By clicking "Post Your Answer", you acknowledge that you have read our updated terms of service, privacy policy and cookie policy, and that your continued use of the website is subject to these policies.

-

Popular posts from this blog

Firebase Auth - with Email and Password - Check user already registered

Image
Clash Royale CLAN TAG #URR8PPP Firebase Auth - with Email and Password - Check user already registered I want to check when a user attempts to signup with createUserWithEmailAndPassword() in Firebase user Authentication method, this user is already registered with my app. createUserWithEmailAndPassword() 8 Answers 8 To detect whether a user with that email address already exists, you can detect when the call to createUserWithEmailAndPassword () fails with auth/email-already-in-use . I see that @Srinivasan just posted an answer for this. createUserWithEmailAndPassword () auth/email-already-in-use Alternatively, you can detect that an email address is already used by calling fetchSignInMethodsForEmail() (previous called fetchProvidersForEmail() ). fetchSignInMethodsForEmail() fetchProvidersForEmail() When the user trying to create an user with same email address, the task response will be "Response: The email address is already in use by another account." mFirebas...
Read more

Dynamically update html content plain JS

Image
Clash Royale CLAN TAG #URR8PPP Dynamically update html content plain JS So I have a script bound in my index.html, which literally has to fetch an array of jsons from an api, then dynamically update my page when get response. But as a result I'm getting an as the only update of my page. here is my script fetch(url) .then((resp) => resp.json()) .then((resp) => resp.results.forEach(item => fetch(item.url) .then((response)=> response.json()) .then((response) => pokeArr.push(response)) .catch(console.log) ) ).catch(console.log) const filler = () => if(!pokeArr) return 0 pokeArr.map((i,j)=> return `<tr>$i.name</tr>` ) const pokeindex = () => document.getElementById('a').appendChild(document.createElement(filler())) pokeindex() When I'm consoling it, I can see in the console all the responses I get, so I'm at least doing the fetching part right. What's parberakan ? What's pokeArr ? – T.J. Crowder Aug 8 at 12...
Read more

Creating a leaderboard in HTML/JS

Image
Clash Royale CLAN TAG #URR8PPP Creating a leaderboard in HTML/JS I'm trying to create a top 10 leaderboard, for now, I've only implemented 3 players, but I'm coming across an issue. My script doesn't seem to be outputting anything on webpage. The purpose of the script is to compare 3 arrays, player1,player2,and player3 solely based off of score. Which is the 2nd index of each array. I want the script to list the players in order of highest score. This method doesn't really seem to be efficient, especially when I'll have to add 7 more players. Could someone suggest perhaps an easier approach, as well as show me why my script wont output the info. Here's the JS function leaderboard() { var player1 = name:"Thomas",date:"01/23/18",score:"201"; var player2 = name:"Michael",date:"03/24/17",score:"943"; var player3 = Name:"Lisa",date:"06/04/18",Score:"79"; if(player1[2]...
Read more