Clash Royale CLAN TAG#URR8PPP

Converting a single char to std::string prepends x01

I'm trying to receive values from an unordered map that has std::string as keys, where some of these strings contain only a single character. All my input is coming from a std::stringstream from which I get each value and cast it to a char, and then converting it to a string using
std::string result 1, character;, which seems to be valid according to the documentation and this answer.

std::string

std::stringstream

std::string result 1, character;

However, when I'm doing so the string gets a x01 prepended (which corresponds to the value 1). This makes the string to not be found in the map. My debugger also confirms that the string is of size 2 with the value "x01H".

Why is this happening and how can I fix it?

#include <iostream>
#include <sstream>
#include <unordered_map>

int main()

const std::unordered_map<std::string, int> map = "H", 1, "BX", 2 ;

std::stringstream temp "Hello world!";
char character = static_cast<char>(temp.get()); // character is 'H'
std::string result 1, character; // string contains "x01H"

std::cout << result << " has length " << result.size() << std::endl; // H has length 2
std::cout << map.at(result) << std::endl; // unordered_map::at: key not found



1 Answer
1

You are using braces , not parenthesis (), unlike the question you link to. That makes it an initializer list, not the constructor you were expecting.

()

1

'x01'

std::string s('a', 'b', 'c')

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