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Using sortBy on multiple elements in a List of Nested Tuples in Scala

Given the following data type [((String, String), Double)] in Scala how would I used the sortBy function to sortby the First String then the second String? There are some answers for sorting on multiple values but what about in the case below?

[((String, String), Double)]

var test =
List((("C","c"),4.3), (("A","c"),1.4), (("C","d"),80.1))

test.sortBy(???).foreach(println)


Output should provide following

(("A","c"),1.4),
(("C","c"),4.3),
(("C","d"),80.1)


2 Answers
2

Since the elements within each tuple ((s1, s2), d) are already in the order (from left to right) you want for the sorting, you can simply do this:

((s1, s2), d)

test.sortBy(identity)
// List[((String, String), Double)] = List(((A,c),1.4), ((C,d),80.1), ((D,c),4.3))


Or, just use sorted:

sorted

test.sorted
// List[((String, String), Double)] = List(((A,c),1.4), ((C,d),80.1), ((D,c),4.3))


You can do that sorting by a tuple where every element, from left to right is more relevant.

var test = List((("D","c"),4.3), (("A","c"),1.4), (("C","d"),80.1))

test.sortBy case ((a,b),c) => (a,b,c) .foreach(println)


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