can i use fgets for accepting strings in character pointer array instead of scanf [duplicate]
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can i use fgets for accepting strings in character pointer array instead of scanf [duplicate]
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Although the below code is working fine.But its showing "segmentation fault" when i am trying to accept the strings using fgets as i want to store strings which might contain spaces.How to accept strings (which might contain spaces)
in character pointer array
int main()
char* nm[5];
char* st;
for(int i=0;i<5;i++)
//fgets(nm[i],30,stdin);
scanf("%ms",&nm[i]);
for(int i=0;i<5;i++)
printf("%sn",nm[i]);
return 0;
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1 Answer
1
nm is a pointer to 5 chars not a pointer to 5 strings, so &nm[2] is the address of the 3rd char in nm. If you change nm to be
char* nm[5][50];
you will have an array of 5 x 50 chars. That should stop the segfault.
nm is not a pointer to 5 chars, but an array of 5 pointers to char.– David Bowling
Aug 12 at 8:37
nm
char
char
This answer is wrong. Even the analysis it gives is wrong.
– alk
Aug 12 at 9:41
BTW, "a pointer to 5 chars" would be defined as
char (*pointer_to_array_of_5_char)[5];– alk
Aug 12 at 9:43
char (*pointer_to_array_of_5_char)[5];
I knew my c was rusty but I didn't think it was that bad 😁
– Neil
Aug 12 at 9:46
Neil please check this link stackoverflow.com/a/50667860/10212490.I think nm[2] points to the base address of 3rd string in the array
– NIKITA AGARWAL
Aug 12 at 7:26