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How to get 2 random numbers divisible by each other?

I'm generating 2 random numbers:

1) The first number must be random from 1 to 30

2) The second number must be random from 1 to 10

I'm simply trying to have the first number divisible by the second number or vice-versa, and finally, alert the result. My question is how to get the result of the division of 2 random numbers? Can anyone point me in the right direction? Thanks a lot in advance!.

Note: the first number must be divisible by the second number.

Here's my code:

var arr = ;
for (var i = 0; i < 2; i++)
do
var firstRandomNumber = Math.floor(Math.random()*30) + 1;
var secondRandomNumber = Math.floor(Math.random()*10) + 1;
if(firstRandomNumber % secondRandomNumber === 0)
correctResult = result;
arr.push(correctResult);

while ((firstRandomNumber % secondRandomNumber === 0));

console.log(arr);


first number divisible by the second number or vice-versa

first number must be divisible by the second number

5 Answers
5

Few things:

while

firstRandomNumber % secondRandomNumber === 0

result

if(firstRandomNumber % secondRandomNumber === 0){

arr.push()

var arr = ;
for (var i = 0; i < 2; i++)
do
var firstRandomNumber = Math.floor(Math.random()*30) + 1;
var secondRandomNumber = Math.floor(Math.random()*10) + 1;
while ((firstRandomNumber % secondRandomNumber !== 0));

console.log('first', firstRandomNumber, 'second', secondRandomNumber);
arr.push(firstRandomNumber / secondRandomNumber);

console.log(arr);

console.log

I would suggest a more functional approach: create a function that creates two random numbers, and returns them if one is divisible by the other. Then, just call that function until you get a truthy result:

function tryGetDivisible()
var firstRandomNumber = Math.floor(Math.random() * 30) + 1;
var secondRandomNumber = Math.floor(Math.random() * 10) + 1;
if (firstRandomNumber % secondRandomNumber === 0)
console.log(firstRandomNumber, secondRandomNumber);
return firstRandomNumber / secondRandomNumber;



let result;
while (!result) result = tryGetDivisible();
const arr = [result];
console.log(arr);

A much simpler approach is to get the first random number, and then try getting the second random number until they are divisible. So here will be the code:

var firstRandomNumber = Math.floor(Math.random()*30) + 1;
while (firstRandomNumber % secondRandomNumber !== 0)
var secondRandomNumber = Math.floor(Math.random()*10) + 1;

console.log(firstRandomNumber + "," + secondRandomNumber);


Since the first must be divisible by the second, my approach would be:

Math.floor(30/firstNumber)

This way, there's no need to do a generate-and-test loop, which could go on an unbounded number of times before a successful pair is generated.

If you want to avoid the while loop, you can pick the first number, then assemble the possible second numbers in an array. Then randomly pick one of these:

while

let first = Math.floor(Math.random() * 10) + 1

// all possible divisible numbers
let factors = Array.from(length: 30, (_, i) => i + 1)
.filter(i => first % i === 0 || i % first === 0)

//pick one
let second = factors[Math.floor(Math.random() * factors.length)]

console.log(first, second)

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