Read text file values and assign it to each value to variable

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Read text file values and assign it to each value to variable



I want to read text file and find the words that starts with 56 in below text and pass each word to a variable and pass to a python file as a parameters.



My sample text file content -


51:40:2e:c0:01:c9:53:e8
56:c9:ce:90:4d:77:c6:03
56:c9:ce:90:4d:77:c6:07
51:40:2e:c0:01:c9:54:80
56:c9:ce:90:12:b4:19:01
56:c9:ce:90:12:b4:19:03



I like to pass to python file as


mytestfile.py var1 var2 var3



var1 should have value 56:c9:ce:90:4d:77:c6:03
var2 should have value 56:c9:ce:90:4d:77:c6:07
var3 should have value 56:c9:ce:90:12:b4:19:01



so on



I wrote code something like below but not working



[#var1 = "51:40:2e:c0:01:c9:53:e8"]
[#var2 = "51:40:2e:c0:01:c9:53:ea"]


filepath = '/root/SDFlex/work/cookbooks/ilorest/files/file.txt'
with open(filepath) as fp:
line = fp.readline()
cnt = 1
while line:
print("Line : ".format(cnt, line.strip()))
line = fp.readline()
cnt += 1



execute "run create volume script" do


command "python SDFlexnimblevolcreate.py #var1 #node['ilorest']['Test0'] #var2 #node['ilorest']['Test1']
cwd "#platformdirectory"
live_stream true



end



Thanks in advance





Are you sure that you need to pass parameters for mytestfile.py in a such way?
– Lev Zakharov
Aug 13 at 2:32



mytestfile.py





I mean as a variable like mytestfile.py var1 var2 var3 var4. I want to assign it to variable that should increase for each value
– Ram Krishna
Aug 13 at 2:34




2 Answers
2



So this code prints string of required variables:


# a.py
with open('file.txt') as f:
result = ' '.join(map(lambda x: f'<x>',
filter(lambda x: x.startswith('56'),
map(str.strip, f))))
print(result, end='')



Output:


<56:c9:ce:90:4d:77:c6:03> <56:c9:ce:90:4d:77:c6:07> <56:c9:ce:90:12:b4:19:01> <56:c9:ce:90:12:b4:19:03>



You can pass result of this program using xargs to some another python program. For example if you have simple program which prints their arguments:


xargs


# b.py
import sys

print(sys.argv)



Than just type in shell:


python3 a.py | xargs python3 b.py



Output:


['b.py', '<56:c9:ce:90:4d:77:c6:03> <56:c9:ce:90:4d:77:c6:07> <56:c9:ce:90:12:b4:19:01> <56:c9:ce:90:12:b4:19:03>']





how to do that using pipe?
– Ram Krishna
Aug 13 at 2:45





Please, read this wiki. You can pass the result of this script to mytestfile.py using pipeline. I will add an example soon.
– Lev Zakharov
Aug 13 at 2:47



mytestfile.py





@RamKrishna updated!
– Lev Zakharov
Aug 13 at 2:55





But the OP deosn't want a pipe, they want the output to be passed as command-line arguments. (This is probably misdirected, though.) The solution to that is xargs, or you can run the second program as a subprocess from the first.
– tripleee
Aug 13 at 3:33



xargs





Still probably not right, take out the -0 (or actually print null-separated output from the first script).
– tripleee
Aug 13 at 3:45


-0



Are you trying to run your mytestfile.py once for each line that starts with '56:', like this:


mytestfile.py


python mytestfile.py 56:c9:ce:90:4d:77:c6:03
python mytestfile.py 56:c9:ce:90:4d:77:c6:07
python mytestfile.py 56:c9:ce:90:12:b4:19:01



Or do you want to run it one time only, giving it all values from the file as arguments, e.g., with your example data:


python mytestfile.py 56:c9:ce:90:4d:77:c6:03 56:c9:ce:90:4d:77:c6:07 56:c9:ce:90:12:b4:19:01



If it is the former (one run per matching line), the easiest way is:


grep '^56' textfile | xargs python mytestfile.py



otherwise, you could do this:


python mytestfile.py `grep '^56' textfile`



note the latter is dependent on having no spaces in the file - and is a bit dangerous if the file is very large (you could run into the command-line length limit).





I want to run python mytestfile.py 56:c9:ce:90:4d:77:c6:03 56:c9:ce:90:4d:77:c6:07 56:c9:ce:90:12:b4:19:01
– Ram Krishna
Aug 13 at 6:36






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