Clash Royale CLAN TAG#URR8PPP

print dictionary keys and values in ordered manner

I have a dictionary with keys and values as shown below.

from datetime import datetime
dic = 'pack1':'stage1','pack2':'stage2','pack3':'stage3','pack4':'stage4'


I want to print the keys and their corresponding values in ordered manner in new line, like

Update at 2018-09-18 09:58:03.263575

The code I tried is given below

print("Update at %snDeliverytttttttState nttt".format(key for key in dic.keys(), val for val in dic.values()) %datetime.now())


But it give the output as

Update at 2018-09-18 09:58:03.263575

The values doesn't correspond to their keys, and the output is given in a single line as a set of lists. How to format the output as my requirement?
(There are whitespaces between 'delivery' and State but stack overflow doesn't show them)

3 Answers
3

Dictionary order is not preserved by default. If you want that for any reason then you need to use OrderedDict instead

You need to loop over your input, you can't do this cleanly in a single format and print operation.

format

print

If the keys only need to match their values, just do:

dic = 'pack1':'stage1','pack2':'stage2','pack3':'stage3','pack4':'stage4'

for k, v in dic.items(): # .viewitems() on Python 2.7
print("ttt".format(k, v))


If you need the output ordered, not just matched up, dict don't provide that guarantee before 3.7 (and don't provide even implementation dependent guarantees until 3.6). You'd need a collections.OrderedDict. You could do a presort though:

dict

collections.OrderedDict

for k, v in sorted(dic.items()): # .viewitems() on Python 2.7
print("ttt".format(k, v))


so the output ordering is predictable.

It is good to note that since Python 3.7, a dict preserves the order in which data is entered. Prior to that, you can use an OrderedDict.

dict

OrderedDict

Although, it seems what you want is to sort the key-value pairs in alphabetical order of keys. In that case, you can use sorted.

sorted

dic = 'pack1': 'stage1', 'pack2': 'stage2', 'pack3': 'stage3', 'pack4': 'stage4'

for k, v in sorted(dic.items()):
print (k + 't' + v)


pack1 stage1
pack2 stage2
pack3 stage3
pack4 stage4


From there you can work on the printing format.

set

set([...])

...

print

__future__

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