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Java String spit using regex with single forward slash not followed by a slash

I want to split the URL by a forward slash, not by two forward slash.

http://www.eclipse.org/swt/snippets/

I want to split above URL as http://www.eclipse.org, swt, snippets.

Code:

url = http://www.eclipse.org/swt/snippets/;
String truncUrl = url.split("/");


Please guide me with regex.

Thanks,

2 Answers
2

You want a combination of a negative lookbehind (that is, "not preceded by") and a negative lookahead (that is, "not followed by"). So you'll split on any / that's not preceded by a / and not followed by a /.

/

/

/

According to the Javadoc for Pattern -

(?<!

)

(?!

)

So the regular expression you want is (?<!/)/(?!/)

(?<!/)/(?!/)

As an additional answer,

you may use this expression ((?:http(s)?://)?[w.&?=%#+:-]+)

((?:http(s)?://)?[w.&?=%#+:-]+)

Example:

import java.util.regex.Pattern;
import java.util.regex.Matcher;
import java.util.List;
import java.util.ArrayList;

public class MyClass
public static void main(String args)
String url = "https://stackoverflow.com/questions/51016377/java-string-spit-using-regex-with-single-forward-slash-not-followed-by-a-slash";
Pattern rgx = Pattern.compile("((?:http(s)?://)?[\w.&?=%#+:-]+)");
Matcher m = rgx.matcher(url);

List<String> list = new ArrayList<>();
while (m.find())
list.add(m.group(1));

list.forEach(System.out::println);




Output:

https://stackoverflow.com
questions
51016377
java-string-spit-using-regex-with-single-forward-slash-not-followed-by-a-slash


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