Reading multiple character arrays in C using scanf [duplicate]
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Reading multiple character arrays in C using scanf [duplicate]
This question already has an answer here:
char a[100],b[100],c[100];
scanf("%[^n]",a);
printf("%s",a);
scanf("%[^n]",b);
printf("%s",b);
The compiler seems to be reading the first read but skips the second read. Why is this happening?
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scanf
fgets
n
Or, if you want to use
scanf, you can consume and discard the newline with scanf("%99[^n]%*c", a);. (Added 99 to avoid buffer overflow).– Johnny Mopp
Aug 6 at 14:57
scanf
scanf("%99[^n]%*c", a);
99
Tip: When I/O is not working as expected, the 1st line of defense coding is to check the result value of the functions.
int cnt = scanf("%[^n]",b); if (cnt != 1) printf("Unexpected scan %dn", cnt); would have helped this code a lot to narrow the issue.– chux
Aug 6 at 16:06
int cnt = scanf("%[^n]",b); if (cnt != 1) printf("Unexpected scan %dn", cnt);
1 Answer
1
Because of un handled Enter
Use fgets()
fgets()
Try this :-
char a[100], b[100], c[100];
fgets(a, 100, stdin);
printf("%s", a);
fgets(b, 100, stdin);
printf("%s", b);
Why is that a problem?
– metasj
Aug 6 at 14:50
The
newline generated in scanning a is assigned to b– anoopknr
Aug 6 at 14:53
newline
a
b
Testing the return value of
fgets() would prevent potential undefined behavior on early end of file.– chqrlie
Aug 6 at 14:58
fgets()
@anoopknr The newline generated in scanning a is assigned to b --> No. with
scanf("%[^n]",b);, b would not get a 'n' assigned.– chux
Aug 6 at 16:08
scanf("%[^n]",b);
b
'n'
Don't use
scanf. Usefgetsand strip of thenif you don't want it– 4386427
Aug 6 at 14:49