How to set Model property, toggle a boolean in Django query?

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How to set Model property, toggle a boolean in Django query?



Is it possible in my Detail view below, to set the boolean within a model to be false ?
I looked through the django documentation (queryset) for something like a .set() method for this, it seems to exist but not applicable to this particular case.
How can I toggle the unread boolean in my Models.py, through my view ?


.set()


unread


Models.py



Also, what am I misunderstanding here and what is the better/appropriate way to do this ?



Models.py:


class Message(models.Model):
recipient = models.ForeignKey(CustomUser, on_delete = models.CASCADE,related_name = 'recipient',null = True)
sender = models.ManyToManyField(CustomUser,related_name = 'messages')
date = models.DateTimeField(auto_now_add=True, blank=True)
subject = models.CharField(max_length = 1000, blank = True)
message = models.TextField(blank=True, null=True)
unread = models.BooleanField(default = True)



Views.py :


### Message detail class
class MessageInboxDetail(DetailView):
'''
This view lets the user view the details of a message created
'''
context_object_name = 'message_detail'
model = Message
template_name = "myInbox/message_detail.html"

def get_context_data(self, **kwargs):
context = super(MessageInboxDetail, self).get_context_data(**kwargs)
context.update(
'message_detail': Message.unread.set(False) ) # Message(unread=True/False)
return context





context['instance'].unread = False and context['instance'].save().
– Willem Van Onsem
Aug 8 at 14:10


context['instance'].unread = False


context['instance'].save()





@WillemVanOnsem I get a linting warning : "Instance of BooleanField has no set member" Then I get a KeyError for 'instance' .
– timi95
Aug 8 at 14:24




1 Answer
1



You do not set the field of a model instance with a .set(..) call, but by assigning to the attribute (behind the curtains, Django has patched the __get__ and __set__ functions).


.set(..)


__get__


__set__



We can thus obtain the message object by retrieving it out of the context (with context['message_detail'], and then change it state, and finally save the updated version to the database. For example:


message


context['message_detail']


class MessageInboxDetail(DetailView):
'''
This view lets the user view the details of a message created
'''
context_object_name = 'message_detail'
model = Message
template_name = "myInbox/message_detail.html"

def get_context_data(self, **kwargs):
context = super(MessageInboxDetail, self).get_context_data(**kwargs)
message = context['message_detail']
message.unread = False
message.save()

return context



I however do not know if it is a good idea to mark a message as read in the detail view, it can result in code duplication, which is usually not a good idea.





" I however do not know if it is a good idea to mark a message as read in the detail view, it can result in code duplication, which is usually not a good idea. " Can you explain further please ? Is there a better/simpler way to implement this feature in django ?
– timi95
Aug 8 at 14:52





@timi95: it might be better to implement a mark_read function in the Message class itself. Furthermore it could happen that if the view fails (or for example the network connection of the user stops working), the message is marked read without the user actually having read the message. If you want to prevent that, an AJAX call to a view that marks messages as read might perhaps be more robust.
– Willem Van Onsem
Aug 9 at 7:16


mark_read


Message






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