Clash Royale CLAN TAG#URR8PPP

Get number of years, months, days, minutes from number of minutes

How to get the total number of monts, days, and minutes from a given minute. Say for example given a value in minutes 93366 should return 2 months ,5 days and 5 hours. This is what I've tried so far.

93366

2 months ,5 days and 5 hours

function convert_minutes($minutes, $output)
if ($minutes >= 43833)
$whole_month = 0;
$decimal_month = 0;
$label = "";
$months = $minutes / 43833;
list($whole_month, $decimal_month) = sscanf($months, '%d.%d');
if ($months > 1)
$label = "months";
else
$label = "month";

$output .= $months . " " . $label;
$decimal_month = "0." . $decimal_month;
if ($decimal_month != 0)
return $this->convert_minutes($decimal_month, $output);
else
return $output;

elseif ($minutes >= 1440)
$whole_day = 0;
$decimal_day = 0;
$label = "";
$days = $minutes / 1440;
list($whole_day, $decimal_day) = sscanf($days, '%d.%d');
if ($days > 1)
$label = "days";
else
$label = "day";

$output .= $days . " " . $label;
$decimal_day = "0." . $decimal_day;
if ($decimal_day != 0)
return $this->convert_minutes($decimal_day, $output);
else
return $output;

elseif ($minutes >= 60)
$whole_minutes = 0;
$decimal_minutes = 0;
$label = "";
$min = $minutes / 60;

list($whole_minutes, $decimal_minutes) = sscanf($min, '%d.%d');
if ($min > 1)
$label = "minutes";
else
$label = "minute";

$output .= $min . " " . $label;
$decimal_minutes = "0." . $decimal_minutes;
if ($decimal_minutes != 0)
return $output . " and " . $decimal_minutes . " minutes";
else
return $output;





EDIT

I just wanted to get the estimate. Assuming 1 hour is 60 minutes and 1 day is 1440 minutes and 1 month is 43,200. I am developing a document tracking system and would just like to calculate how long a document stayed in a particular office based on the date received and date released.

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