Clash Royale CLAN TAG#URR8PPP

Write KML file from another

I'm trying to:

- read a KML file
- remove the Placemark element if name = 'ZONE'
- write a new KML file without the element


This is my code:

from pykml import parser
kml_file_path = '../Source/Lombardia.kml'

removeList = list()

with open(kml_file_path) as f:
folder = parser.parse(f).getroot().Document.Folder

for pm in folder.Placemark:
if pm.name == 'ZONE':
removeList.append(pm)
print pm.name

for tag in removeList:
parent = tag.getparent()
parent.remove(tag)
#Write the new file
#I cannot reach the solution help me


and this is the KML:

<?xml version="1.0" encoding="UTF-8"?>
<kml xmlns="http://earth.google.com/kml/2.2">
<Document>
<name>Lombardia</name>
<Style>
...
</Style>
<Folder>
<Placemark>
<name>ZOGNO</name>
<styleUrl>#FEATURES_LABELS</styleUrl>
<Point>
<coordinates>9.680530595139061,45.7941656233647,0</coordinates>
</Point>
</Placemark>
<Placemark>
<name>ZONE</name>
<styleUrl>#FEATURES_LABELS</styleUrl>
<Point>
<coordinates>10.1315885854064,45.7592449779275,0</coordinates>
</Point>
</Placemark>
</Folder>
</Document>
</kml>


The problem is that when I write the new KML file this still has the element I want to delete.
In fact, with I want to delete the element that contains name = ZONE.
What i'm doing wrong?
Thank you.

--- Final Code
This is the working code thanks to @Dawid Ferenczy:

from lxml import etree
import pykml
from pykml import parser

kml_file_path = '../Source/Lombardia.kml'

# parse the input file into an object tree
with open(kml_file_path) as f:
tree = parser.parse(f)

# get a reference to the "Document.Folder" node
folder = tree.getroot().Document.Folder

# iterate through all "Document.Folder.Placemark" nodes and find and remove all nodes
# which contain child node "name" with content "ZONE"
for pm in folder.Placemark:
if pm.name == 'ZOGNO':
parent = pm.getparent()
parent.remove(pm)

# convert the object tree into a string and write it into an output file
with open('output.kml', 'w') as output:
output.write(etree.tostring(folder, pretty_print=True))


tree

pykml

tree

etree

lxml

2 Answers
2

You have the following issues in your code:

folder = parser.parse(f).getroot().Document.Folder

removeList

Try the following code:

from lxml import etree
from pykml import parser

kml_file_path = './input.kml'

# parse the input file into an object tree
with open(kml_file_path) as f:
tree = parser.parse(f)

# get a reference to the "Document.Folder" node
folder = tree.getroot().Document.Folder

# iterate through all "Document.Folder.Placemark" nodes and find and remove all nodes
# which contain child node "name" with content "ZONE"
for pm in folder.Placemark:
if pm.name == 'ZONE':
parent = pm.getparent()
parent.remove(pm)

# convert the object tree into a string and write it into an output file
with open('output.kml', 'w') as output:
output.write(etree.tostring(tree, pretty_print=True))


It's very simple:

tree

Consider XSLT, the special purpose language designed to transform XML files. And because KML files are XML files, this solution is viable. Python's third-party module, lxml can run XSLT 1.0 scripts and do so without a single loop.

lxml

Specifically, the XSLT script runs the Identity Transform to copy entire document as is. Then, script runs an empty template on the element (conditional to specific logic) to remove that element. To accommodate the default namespace, a prefix, doc, is used for XPath search.

XSLT (save as .xsl file, a special .xml file to be loaded in Python below)

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:doc="http://earth.google.com/kml/2.2">
<xsl:output method="xml" indent="yes"/>
<xsl:strip-space elements="*"/>

<xsl:template match="@* | node()">
<xsl:copy>
<xsl:apply-templates select="@* | node()"/>
</xsl:copy>
</xsl:template>

<xsl:template match="doc:Placemark[doc:name='ZONE']"/>

</xsl:stylesheet>


XSLT Fiddle Demo

Python

import lxml.etree as et

# LOAD XML AND XSL
doc = et.parse('/path/to/Input.xml')
xsl = et.parse('/path/to/XSLT_Script.xsl')

# CONFIGURE TRANSFORMER
transform = et.XSLT(xsl)

# RUN TRANSFORMATION
result = transform(doc)

# PRINT RESULT
print(result)

# SAVE TO FILE
with open('output.xml', 'wb') as f:
f.write(result)


Output

<?xml version="1.0" encoding="UTF-8"?>
<kml xmlns="http://earth.google.com/kml/2.2">
<Document>
<name>Lombardia</name>
<Style>
...
</Style>
<Folder>
<Placemark>
<name>ZOGNO</name>
<styleUrl>#FEATURES_LABELS</styleUrl>
<Point>
<coordinates>9.680530595139061,45.7941656233647,0</coordinates>
</Point>
</Placemark>
</Folder>
</Document>
</kml>


By clicking "Post Your Answer", you acknowledge that you have read our updated terms of service, privacy policy and cookie policy, and that your continued use of the website is subject to these policies.