two operations on each element of a list

I would like to achieve the following lines in just one line:

list1 = [abs(x) for x in list1] list1 = list(map(lambda x:x-1, list1))

I tried

list1 = [abs(x) and x-1 for x in list1]

even though I don't think there is such syntax, but anyway it didn't work.

[abs(x)-1 for x in list1] is it what you want?
– Saeed
Aug 12 at 2:49

2 Answers
2

and is a logical operator in Python, it cannot be used in this condition.

and

why not try

[abs(x) - 1 for x in list1]

thx, do you know if we can do two operations in other cases in just one line?
– Lelo
Aug 12 at 3:02

@Lelo it's ok, you can use lambda to do the more complicated operation in one line. And how to achieve it depends on what the problem is.
– pwxcoo
Aug 12 at 3:05

lambda

what do you mean @Lelo? You can string lambda functions together, if that interests you
– kevinkayaks
Aug 12 at 3:05

list1 = list(map(lambda x: abs(x)-1,list1))

Interestingly this is slower than

list1 = [abs(x) - 1 for x in list1]

Anyone know why?

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