Clash Royale CLAN TAG#URR8PPP

Python Programming - to modify a list item in a dictionary

Question: # Write a program to modify the email addresses in the records dictionary to reflect this change

records

records = 57394: ['Suresh Datta', 'suresh@example.com'], 48539: ['ColetteBrowning', 'colette@example.com'], 58302: ['Skye Homsi','skye@example.com'], 48502: ['Hiroto Yamaguchi', 'hiroto@example.com'], 48291: ['Tobias Ledford', 'tobias@example.com'], 48293: ['Jin Xu', 'jin@example.com'], 23945: ['Joana Dias', 'joana@example.com'], 85823: ['Alton Derosa', 'alton@example.com']


I have iterated through the dictionary and created a new list with the values and split the email at @ and was able to change the the email from .com to .org.

My approach was to join the changed email and change the values of the dictionary. However, I keep on getting a TypeError: sequence item 0: expected str instance, list found

my code :

lst2 =

for value in records.values():
lst2.append(value[1].split('@'))


for items in lst2:
items[1] = 'examples.org'

for items in lst2:
','.join(lst2)


','.join(lst2)

lst2

3 Answers
3

The issue is in your final for loop:

for items in lst2:
','.join(lst2)


You are joining should be joining items not lst2. However if you fix that it still won't work. You need to create a third list and add the values to it like this:

lst3 =
for items in lst2:
lst3.append('@'.join(items))


Then, lst3 will have the properly formatted emails.

You can do a one-liner list-comprehension for, then iterate and do join the split of i with ',', so try this:

i

','

print([','.join(i[1].replace('.com','.org').split('@')) for i in records.values()])


Output:

['suresh,example.org', 'colette,example.org', 'skye,example.org', 'hiroto,example.org', 'tobias,example.org', 'jin,example.org', 'joana,example.org', 'alton,example.org']


Or:

print(['@'.join(i[1].replace('.com','.org').split('@')) for i in records.values()])


Output:

['suresh@example.org', 'colette@example.org', 'skye@example.org', 'hiroto@example.org', 'tobias@example.org', 'jin@example.org', 'joana@example.org', 'alton@example.org']


Or if want to edit dict:

print(k:[i.replace('.com','.org') for i in v] for k,v in records.items())


Output:

57394: ['Suresh Datta', 'suresh@example.org'], 48539: ['ColetteBrowning', 'colette@example.org'], 58302: ['Skye Homsi', 'skye@example.org'], 48502: ['Hiroto Yamaguchi', 'hiroto@example.org'], 48291: ['Tobias Ledford', 'tobias@example.org'], 48293: ['Jin Xu', 'jin@example.org'], 23945: ['Joana Dias', 'joana@example.org'], 85823: ['Alton Derosa', 'alton@example.org']


Try the following code

records = 57394: ['Suresh Datta', 'suresh@example.com'], 48539: ['ColetteBrowning', 'colette@example.com'], 58302: ['Skye Homsi','skye@example.com'], 48502: ['Hiroto Yamaguchi', 'hiroto@example.com'], 48291: ['Tobias Ledford', 'tobias@example.com'], 48293: ['Jin Xu', 'jin@example.com'], 23945: ['Joana Dias', 'joana@example.com'], 85823: ['Alton Derosa', 'alton@example.com']
for key, value in records.items():
new_data =
for data in value:
new_data.append(data.replace('.com', '.org'))
records[key] = new_data

print(records)


57394: ['Suresh Datta', 'suresh@example.org'], 48539: ['ColetteBrowning', 'colette@example.org'], 58302: ['Skye Homsi', 'skye@example.org'], 48502: ['Hiroto Yamaguchi', 'hiroto@example.org'], 48291: ['Tobias Ledford', 'tobias@example.org'], 48293: ['Jin Xu', 'jin@example.org'], 23945: ['Joana Dias', 'joana@example.org'], 85823: ['Alton Derosa', 'alton@example.org']

By clicking "Post Your Answer", you acknowledge that you have read our updated terms of service, privacy policy and cookie policy, and that your continued use of the website is subject to these policies.