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Java Scanner nextLine Issue, additional enter is needed

I'm studying java I/O. There is some issue on my code.
I want to print

[0, 0, 1]
[1, 0, 1]
[0, 0, 1]
[2, 0, 1]
[10, 0, 5]


But additional enter is needed.

public static void main(String args)
Scanner sc = new Scanner(System.in);
int tc = sc.nextInt();
sc.nextLine();
System.out.println();

for (int i = 0; i < tc; i++)
int line = sc.nextInt();
sc.nextLine();

for (int j = 0; j < line; j++)
System.out.println(i+""+j);
int st = Arrays.stream(sc.nextLine().split(" "))
.mapToInt(Integer::parseInt).toArray();
System.out.println(Arrays.toString(st));





Below is input & output. And I don't know why [10, 0, 5] is not shown. If I push enter key, then [10, 0, 5] appears.

Input
2
2
0 0 1
1 0 1
3
0 0 1
2 0 1
10 0 5

Output
[0, 0, 1]
[1, 0, 1]
[0, 0, 1]
[2, 0, 1]
(additional enter)
[10, 0, 5]


tc

nextLine

nextInt

2 Answers
2

read the java doc for nextLine method.

nextLine

Since this method continues to search through the input looking for a
line separator, it may buffer all of the input searching for the line
to skip if no line separators are present.

This nextLine call blocks until it finds line seperator, which is the additional enter.

int st = Arrays.stream(sc.nextLine().split(" "))
.mapToInt(Integer::parseInt).toArray();


//your code is working as expected for given input after removing some print statements
public static void main(String args)
Scanner sc = new Scanner(Paths.get(System.in));
int tc = sc.nextInt();
sc.nextLine();
//remove extra print statement
// System.out.println();

for (int i = 0; i < tc; i++)
int line = sc.nextInt();
sc.nextLine();

for (int j = 0; j < line; j++)
//remove extra print statement
// System.out.println(i+""+j);
int st = Arrays.stream(sc.nextLine().split(" ")).mapToInt(Integer::parseInt).toArray();
System.out.println(Arrays.toString(st));





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