I try to get all data included in [] (not specific tokens!)
Clash Royale CLAN TAG#URR8PPP
I try to get all data included in (not specific tokens!)
I try to get all data included in (not specific tokens!)
I try with loop but its give only 1 parameter.
Example what I need:
set "x=Stackoverflow [I need it] and [I need this too] and [this too]"
output => I need it, I need this too, this too
Tried to do:
for /f "delims=" %%a in ("%x%") do (
echo %%a
)
I edit my question
– dauzduz TV
Aug 10 at 13:09
So what happened, and how was it contrary to your expectations? Enter
For /? at the Command Prompt, read the usage information, paying particular attention to the tokens as well as delims .– Compo
Aug 10 at 13:11
For /?
tokens
delims
the code looping only 1 time, like code running and giving 1 echo of x variable: output => Stackoverflow
– dauzduz TV
Aug 10 at 13:14
As I told you, read the usage for the command you're using.
– Compo
Aug 10 at 13:17
2 Answers
2
A very simple method:
@echo off
setlocal EnableDelayedExpansion
set "x=Stackoverflow [I need it] and [I need this too] and [this too]"
set "output=" & set "p=%x:]=" & set "output=!output!, !p:*[=!" & set "p=%"
echo output =^> %output:~2%
Output:
output => I need it, I need this too, this too
For an explanation of the method used, you should remove the @echo off line, run the program and carefully review the executed code. If you want further explanations, then review this topic.
@echo off
you could use "tokens=2,4,6,8,10,12 delims=", but it is difficult to post-process the result (removing additional commas/spaces).
The same effect can be reached by preprocessing the string and splitting with a plain for loop. The flag variable takes care of using each second token only. I added a _ in front of the string to correctly process strings that start with a [. set /a "flag=(flag+1) %% 2" alternates the flag variable between 0 and 1.
"tokens=2,4,6,8,10,12 delims="
for
flag
_
[
set /a "flag=(flag+1) %% 2"
flag
0
1
@echo off
setlocal enabledelayedexpansion
set "x=[this] not [that] not [yes] no [in] out"
set "y=_%x:[=","%"
set "y=%y:]=","%"
set flag=0
for %%a in ("%y%") do (
if !flag!==1 set "result=!result!, %%~a"
set /a "flag^=1"
)
if defined result set "result=%result:~2%"
echo output = %result%
Output:
output = this, that, yes, in
set /a "flag=(flag+1) %% 2" can be simplified to set /a "flag^=1". And maybe set result=!result!, "%%~a" so later on each extracted token can be accessed separately by another naked FOR though not sure if that is what the OP wanted. +1– sst
Aug 10 at 16:33
set /a "flag=(flag+1) %% 2"
set /a "flag^=1"
set result=!result!, "%%~a"
FOR
I give u upvote but I said I dont know where placed in string and not a fact that the exists any 2 tokens, I used other way
– dauzduz TV
Aug 10 at 16:34
@dauzduzTV, Did you test the code at all? It doesn't matter where in the string,
if "%x%"=="%x:[=%". And what was the other way you used?– sst
Aug 10 at 17:07
if "%x%"=="%x:[=%"
added a line to care for "no
" and implemented @sst's "flag" method (never used OR before with set /a, but yes - very useful)– Stephan
Aug 10 at 17:53
"
OR
set /a
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What we now need is an example of what you've tried, with an explanation of what happened when you did so. Note that this site is not a free code writing service.
– Compo
Aug 10 at 13:05