Clash Royale CLAN TAG#URR8PPP

How to recreate the any? method in Ruby

I am trying to recreate the enumerable module in Ruby. I am up to the any? method and having difficulty returning true or false. Instead each array item is returned 1 by 1.. Here is my code:

def my_any?
return self.to enum unless block_given?
self.each do |i|
return true if i == yield(i)
end
end

nums = [3,5,7,3,6,10,20,16]

puts nums.my_any?x==6


Any ideas where I am going wrong?

2 Answers
2

You have two issues:

return false

each

return true if cond

any?

i == yield(i)

yield(i)

(The to enum bit sounds off too, but that's unrelated to your question.)

to enum

Slotting those changes into your code:

def my_any?
# FIXME: return self.to enum unless block_given?
self.each do |i|
return true if yield i
end
false
end


self

self

You have three issues with your code: you should return an enumerator for this method when called without block, you should check just what yield returns, and you should explicitly return false on fail:

yield

false

def my_any?
return to_enum(:my_any?) unless block_given?
each return true if yield(i)
false
end

nums = [3,5,7,3,6,10,20,16]

puts nums.my_any?
#⇒ true
lazy = nums.my_any?
lazy.each
#⇒ true


Or, I would better use break:

break

def my_any?
return to_enum(:my_any?) unless block_given?

each i == true
end


Enumerable

true

false

nums.any?.with_index x <= 6 && i >2

Enumerable#any?

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